
X=-5/13 xЭ(п/2,п),cos x/2


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вот ответ думаю правильно,удачи




It looks like you have an equation and some trigonometric functions involved. Let's break it down step by step:
X = -5/13 This is a simple equation where X is equal to -5/13.
x ∈ (π/2, π) This notation indicates that the variable x belongs to the open interval between π/2 (exclusive) and π (exclusive). In other words, x is greater than π/2 but less than π.
cos(x/2) This is a trigonometric function. You want to calculate the cosine of x divided by 2.
Now, let's find the value of cos(x/2) when x belongs to the specified interval:
Given that x ∈ (π/2, π), we can see that x/2 will be in the interval (π/4, π/2). To calculate cos(x/2), we can use the properties of the cosine function:
cos(π/4) < cos(x/2) < cos(π/2)
cos(π/4) is equal to √2/2, and cos(π/2) is equal to 0.
So, we have:
√2/2 < cos(x/2) < 0
Therefore, cos(x/2) lies between √2/2 and 0 for x ∈ (π/2, π).
Now, if you want to calculate the value of cos(x/2) when x = -5/13, you can plug it into the equation:
cos(-5/13 / 2)
cos(-5/26)
This will give you the cosine of -5/26, which is a specific numerical value. You can calculate this using a calculator or software.


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