Question

Y²-2xy-3x²=0 y²-xy-2xy=4

Answer 1

Можешь не благодарить)

Answer 2

It seems like you have two equations involving variables x and y. Let's work on solving this system of equations:

1. $y^2 - 2xy - 3x^2 = 0$
2. $y^2 - xy - 2xy = 4$

Let's simplify equation (2) by combining like terms:

$y^2 - 3xy = 4$

Now, we can use the method of substitution to solve this system. We can isolate y in equation (2) and then substitute it into equation (1):

From equation (2), we have:

$y^2 - 3xy = 4$

$y^2 = 4 + 3xy$

Now, substitute this expression for $y^2$ into equation (1):

$(4 + 3xy) - 2xy - 3x^2 = 0$

Now, simplify this equation:

$4 + 3xy - 2xy - 3x^2 = 0$

Combine like terms:

$4 + xy - 3x^2 = 0$

Now, isolate xy:

$xy = 3x^2 - 4$

Now, you have the relationship between x and y in terms of x:

$xy = 3x^2 - 4$

You can use this equation to solve for y in terms of x if needed. If you have a specific value of x, you can substitute it into this equation to find the corresponding y value.