Question

N3(x+3)(x² - 1) = (x²+2x - 3) (x + 1)​

Answer 1

(x+3)(x^2-1)=(x^2+2x-3)(x+1)
x^3-x+3x^2-3=x^3+x^2+2x^2+2x-3x-3
-x+3x^2=x^2+2x^2+2x-3x
-x+3x^2=3x^2-x
x-любое число

Answer 2

To solve the equation N3(x+3)(x² - 1) = (x²+2x - 3)(x + 1), you can start by simplifying both sides of the equation and then solving for the variable x. Here are the steps:

1. Distribute the factors on both sides of the equation:

3(x+3)(x² - 1) = (x²+2x - 3)(x + 1)

2. Now, expand each of the expressions:

3(x³ - x + 3x² - 3) = (x³ + x² + 2x² + 2x - 3x - 3)

3. Continue to simplify each side of the equation:

3x³ - 3x + 9x² - 9 = x³ + 3x² + 2x² + 2x - 3x - 3

4. Combine like terms on both sides of the equation:

3x³ - 3x + 9x² - 9 = x³ + 5x² - x - 3

5. Move all the terms to one side of the equation to set it equal to zero:

3x³ - x³ + 9x² - 5x² - 3x + x - 9 + 3 = 0

6. Simplify further:

2x³ + 4x² - 3x - 6 = 0

7. Now, you have a cubic equation in terms of x. To solve this equation, you can attempt to factor it or use numerical methods (such as the rational root theorem, synthetic division, or a calculator).

If you attempt to factor it, you may need to use methods like grouping or the Rational Root Theorem to find its roots. If you'd like to proceed with a specific method or need further assistance, please let me know.