Question

(7x^2-8y^2)(-x^2+3y^2)

Answer 1

(7x²-8y²)(-x²+3y²)=-7x⁴+21x²y²+8x²y²-24y⁴= -7x⁴+29x²y²-24y⁴

Answer 2

To simplify the expression $(7x^2 - 8y^2)(-x^2 + 3y^2)$, you can use the distributive property (FOIL method) to multiply the two binomials together. FOIL stands for First, Outer, Inner, Last, which means you multiply the terms in the first, outer, inner, and last positions.

Here's how you can do it step by step:

1. First: Multiply the first terms of each binomial. $7x^2 \cdot (-x^2) = -7x^4$

2. Outer: Multiply the outer terms of each binomial. $7x^2 \cdot 3y^2 = 21x^2y^2$

3. Inner: Multiply the inner terms of each binomial. $-8y^2 \cdot (-x^2) = 8x^2y^2$

4. Last: Multiply the last terms of each binomial. $-8y^2 \cdot 3y^2 = -24y^4$

Now, combine all these results:

$-7x^4 + 21x^2y^2 + 8x^2y^2 - 24y^4$

Combine like terms:

$-7x^4 + (21x^2y^2 + 8x^2y^2) - 24y^4$

$-7x^4 + 29x^2y^2 - 24y^4$

So, the simplified expression is $-7x^4 + 29x^2y^2 - 24y^4$.