Question

(0,1z+0,3y)(0,01z2−0,03zy+0,09y2) .

Answer 1

=0,01(0,01z²-0,03zy+0,09y²)+0,3y(0,1z²-0,03zy+0,09y²)=0,01z³+0,027yz²+0,027y³

•если вы имеете в виду степень, то ставьте перед ней "^", типа 3^3=3³

Answer 2

To multiply the two expressions $(0.1z + 0.3y)$ and $(0.01z^2 - 0.03zy + 0.09y^2)$, you can use the distributive property (FOIL method).

Here's the step-by-step multiplication:

$(0.1z + 0.3y)(0.01z^2 - 0.03zy + 0.09y^2)$

First, multiply each term in the first expression by each term in the second expression:

1. Multiply $0.1z$ by each term in the second expression: $(0.1z)(0.01z^2) = 0.001z^3$ $(0.1z)(-0.03zy) = -0.003zy^2$ $(0.1z)(0.09y^2) = 0.009zy^2$

2. Multiply $0.3y$ by each term in the second expression: $(0.3y)(0.01z^2) = 0.003z^2y$ $(0.3y)(-0.03zy) = -0.009zy^2$ $(0.3y)(0.09y^2) = 0.027y^3$

Now, add up all these products:

$0.001z^3 - 0.003zy^2 + 0.009zy^2 + 0.003z^2y - 0.009zy^2 + 0.027y^3$

Now, simplify by combining like terms:

$0.001z^3 + 0.003z^2y + 0.027y^3$

So, the product of $(0.1z + 0.3y)$ and $(0.01z^2 - 0.03zy + 0.09y^2)$ is $0.001z^3 + 0.003z^2y + 0.027y^3$.