Question

(9a+1)(2aв квадрате-2а+5)

Answer 1

Ответ:

$(9a+1)(2a {}^{2} -2a+5) = 18a {}^{3} - 18a {}^{2} + 45a + 2a {}^{2} - 2a + 5 = 18a {}^{3} + 20a {}^{2} + 43a + 5$

Answer 2

To multiply the two expressions (9a+1) and (2a^2-2a+5), you can use the distributive property or FOIL method (First, Outer, Inner, Last). Here's how you can do it:

(9a+1)(2a^2-2a+5)

First, multiply the terms in the first expression by each term in the second expression:

First: (9a) * (2a^2) = 18a^3 Outer: (9a) * (-2a) = -18a^2 Inner: (1) * (2a^2) = 2a^2 Last: (1) * (-2a) = -2a

Now, combine these terms:

18a^3 - 18a^2 + 2a^2 - 2a

Next, simplify the expression by combining like terms:

18a^3 - 16a^2 - 2a

So, the product of (9a+1) and (2a^2-2a+5) is 18a^3 - 16a^2 - 2a.