Question

(9a+1)(2aв квадрате-2а+5)

Answer 1

Ответ:

$(9a+1)(2a {}^{2} -2a+5) = 18a {}^{3} - 18a {}^{2} + 45a + 2a {}^{2} - 2a + 5 = 18a {}^{3} + 20a {}^{2} + 43a + 5$

Answer 2

To multiply the two expressions, (9a + 1) and (2a^2 - 2a + 5), you can use the distributive property (also known as FOIL for binomials). Here's how you do it:

(9a + 1)(2a^2 - 2a + 5)

= 9a * (2a^2 - 2a + 5) + 1 * (2a^2 - 2a + 5)

Now, let's multiply each term:

First term: 9a * 2a^2 = 18a^3 Second term: 9a * (-2a) = -18a^2 Third term: 9a * 5 = 45a

Now, let's multiply the constants:

Fourth term: 1 * 2a^2 = 2a^2 Fifth term: 1 * (-2a) = -2a Sixth term: 1 * 5 = 5

Now, we can combine like terms:

18a^3 - 18a^2 + 45a + 2a^2 - 2a + 5

Combine the like terms:

18a^3 - 16a^2 + 43a + 5

So, the product of (9a + 1) and (2a^2 - 2a + 5) is:

18a^3 - 16a^2 + 43a + 5