Question

-x²+3=0-0,1x²+10=0​

Answer 1

Объяснение:

-x²=-3

x=±√3

-0,1x²=-10

x²=100

x=±10

y²=1/9

y=±1/9

Answer 2

It looks like you've provided two quadratic equations. Let's solve each of them:

1. -x² + 3 = 0:

To solve for x, you can start by moving the constant term to the other side of the equation:

-x² = -3

Now, divide both sides by -1 to isolate x²:

x² = 3

To find the value of x, take the square root of both sides. Remember to consider both the positive and negative square roots:

x = ±√3

So, the solutions for the first equation are x = √3 and x = -√3.

2. 0.1x² + 10 = 0:

To solve for x in this equation, start by subtracting 10 from both sides:

0.1x² = -10

Now, divide both sides by 0.1 to isolate x²:

x² = -10 / 0.1 x² = -100

Take the square root of both sides, considering both positive and negative square roots:

x = ±√(-100)

However, the square root of a negative number is not a real number. It is a complex number. So, there are no real solutions to the second equation. The solutions are complex numbers:

x = ±10i

Here, "i" represents the imaginary unit, where i² = -1. So, the solutions are x = 10i and x = -10i.