Question

1)ctg(45°-a)=2 ,tga=?2)tg a=1/3,tg(45°-a)-?​

Answer 1

Ответ:

вот ето может ответ надеюсь да

Answer 2

Let's solve each of the trigonometric equations step by step:

1. ctg(45°-a) = 2

To find the value of tg(a), we can start by finding the value of ctg(45°-a) and then take the reciprocal.

ctg(45°-a) = 2

First, let's find the cotangent of (45°-a):

ctg(45°-a) = 2

We know that ctg(45°) = 1 because the tangent and cotangent of complementary angles are reciprocals of each other.

So, ctg(45°-a) = 1/tg(45°-a) = 2

Now, we can solve for tg(45°-a):

1/tg(45°-a) = 2

Cross-multiply:

tg(45°-a) = 1/2

Now, we need to find tg(a):

tg(a) = tg(45° - (45° - a))

tg(a) = tg(45° - 45° + a)

tg(a) = tg(a)

So, tg(a) = 1/2.

2. tg(a) = 1/3, find tg(45°-a) - ?

We already know that tg(a) = 1/3. Now, let's find tg(45°-a):

tg(45°-a) = tg(45° - (45° - a))

tg(45°-a) = tg(45° - 45° + a)

tg(45°-a) = tg(a)

Now, we need to find tg(45°-a) - ?:

tg(45°-a) - ? = tg(a) - ?

Since we know tg(a) = 1/3, the equation becomes:

1/3 - ? = tg(a) - ?

Now, we need more information or a specific value for the "?," as it cannot be determined from the given information. If you have a specific value for "?," please provide it, and we can calculate the result accordingly.