Question

Log22(4x-33)=log22 3

Answer 1

Ответ:

ОДЗ X>0

log22(4x-33)=log22 3

4x-33=3

4x=36

x=9

Объяснение:

Answer 2

To solve the equation log₂(4x - 33) = log₂(3), you can use the property of logarithms that states if two logarithms with the same base are equal, then their arguments must be equal. In this case, both logarithms have a base of 2, so you can set the arguments equal to each other:

4x - 33 = 3

Now, you can solve for x:

4x = 3 + 33 4x = 36

Now, divide both sides by 4 to isolate x:

x = 36 / 4 x = 9

So, the solution to the equation is x = 9.