Question

1 ) m²-49 =2 ) 4Ь²-121с²=памагите паж срочно​

Answer 1

Ответ:

1)м в квадрате -7 в квадрате

2)2в квадрате б в квадрате - 11в квадрате с в квадрате

Объяснение:

Answer 2

1. To solve the equation $m^2 - 49 = 0$, you can use the difference of squares formula. It can be rewritten as $(m + 7)(m - 7) = 0$.

This equation has two solutions: $m + 7 = 0$ => $m = -7$ $m - 7 = 0$ => $m = 7$

So, the solutions are $m = -7$ and $m = 7$.

2. To solve the equation $4b^2 - 121c^2 = 0$, you can first notice that it's also a difference of squares. You can rewrite it as $(2b + 11c)(2b - 11c) = 0$.

This equation has two solutions: $2b + 11c = 0$ => $2b = -11c$ => $b = -\frac{11}{2}c$ $2b - 11c = 0$ => $2b = 11c$ => $b = \frac{11}{2}c$

So, the solutions are $b = -\frac{11}{2}c$ and $b = \frac{11}{2}c$.