Question

5x - 2y = 33х2 – 8y = -5​

Answer 1

Ответ:

5x-2y=3

5x-2y-3=0

6x-8y=-5

Answer 2

It seems like you have a system of two equations with two variables:

1. 5x - 2y = 33
2. 2x^2 - 8y = -5

You can solve this system of equations using various methods, such as substitution, elimination, or graphing. In this case, I'll use the substitution method.

Let's solve the first equation for x:

1. 5x - 2y = 33

First, add 2y to both sides:

5x = 33 + 2y

Now, divide both sides by 5 to isolate x:

x = (33 + 2y)/5

Now, we can substitute this expression for x into the second equation:

2x^2 - 8y = -5

2((33 + 2y)/5)^2 - 8y = -5

Now, we need to simplify this equation and solve for y:

Let's first square the expression:

2((33 + 2y)/5)^2 = 2(1089 + 132y + 4y^2)/25

Now, subtract 8y from both sides:

2(1089 + 132y + 4y^2)/25 - 8y = -5

Now, let's clear the fraction by multiplying both sides by 25:

2(1089 + 132y + 4y^2) - 200y = -125

Now, distribute the 2 on the left side:

2178 + 264y + 8y^2 - 200y = -125

Combine like terms:

8y^2 + 64y + 2178 = -125

Now, subtract -125 from both sides:

8y^2 + 64y + 2178 + 125 = 0

8y^2 + 64y + 2303 = 0

Now, we have a quadratic equation in terms of y. You can solve this quadratic equation using the quadratic formula:

y = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 8, b = 64, and c = 2303. Plug these values into the quadratic formula to find the values of y. Once you have the values of y, you can substitute them back into the expression for x that we found earlier:

x = (33 + 2y)/5

This will give you the corresponding values of x for each value of y.