Question

3+(2x+3)²=4(x-6)(x+6)​

Answer 1

3+(2х+3)^2=4(х-6)(х+6)

3+4х^2+12х+9=4(х^2-36)

3+4х^2+12х+9=4х^2-144

3+12х+9=-144

12+12х=-144

12х=-144-12

12х=-156

х=-13

Ответ: х=-13

Answer 2

To solve the equation $3 + (2x + 3)^2 = 4(x - 6)(x + 6)$, follow these steps:

Step 1: Expand and simplify both sides of the equation.

Expand the left side by squaring the binomial:

$3 + 4x^2 + 12x + 9 = 4(x^2 - 36)$

Now simplify both sides:

$4x^2 + 12x + 12 = 4x^2 - 144$

Step 2: Subtract $4x^2$ from both sides to eliminate the quadratic term:

$12x + 12 = -144$

Step 3: Next, subtract 12 from both sides to isolate the variable $x$:

$12x = -144 - 12$

$12x = -156$

Step 4: Finally, divide both sides by 12 to solve for $x$:

$x = \frac{-156}{12}$

Simplify the right side:

$x = -13$

So, the solution to the equation $3 + (2x + 3)^2 = 4(x - 6)(x + 6)$ is $x = -13$.