Question

3) (6 - y) + y - 18y2 <0;​

Answer 1

Надеюсь вы поняли )))))))

Answer 2

Ответ

-36y<-6

вот ответ

Answer 3

To solve the inequality (6 - y) + y - 18y^2 < 0, you'll want to find the values of y that satisfy this inequality. Here are the steps to do that:

1. Combine like terms on the left side of the inequality:

(6 - y) + y - 18y^2 = 6 - 18y^2

So, the inequality becomes:

6 - 18y^2 < 0

2. Subtract 6 from both sides of the inequality:

-18y^2 < -6

3. Divide both sides by -1 (note that when dividing by a negative number, the direction of the inequality sign changes):

18y^2 > 6

4. Divide both sides by 18:

y^2 > 6/18

y^2 > 1/3

5. Now, take the square root of both sides. Remember to consider both the positive and negative square roots:

y > ±√(1/3)

6. Simplify the square root:

y > ±√(1/3)

y > ±(1/√3)

y > ±(√3/3)

So, the solution to the inequality is:

y > √3/3 or y < -√3/3

This means that y is greater than the square root of 3 divided by 3 or less than the negative square root of 3 divided by 3 for the inequality to be satisfied.