Question

(0,4t+2s)(0,16t^2-0,8ts+4s^2) ​

Answer 1

Ответ:

$(0.4t+2s)(0.16t^{2}-0.8ts+4s^{2})=(0.4t)^{3}+(2s)^{3} = 0.064t^{3}+8s^{3}$

Answer 2

It seems like you want to multiply the expressions (0,4t+2s) and (0,16t^2-0,8ts+4s^2). However, the notation you've used, with commas instead of multiplication operators or placeholders for variables, is not standard. Assuming you want to multiply these two expressions, you can do it as follows:

(0.4t + 2s)(0.16t^2 - 0.8ts + 4s^2)

To multiply these two expressions, you can use the distributive property (FOIL method for binomials):

(0.4t)(0.16t^2 - 0.8ts + 4s^2) + (2s)(0.16t^2 - 0.8ts + 4s^2)

Now, perform the multiplication for each term:

First term: (0.4t)(0.16t^2) = 0.064t^3 Second term: (0.4t)(-0.8ts) = -0.32t^2s Third term: (0.4t)(4s^2) = 1.6ts^2

Fourth term: (2s)(0.16t^2) = 0.32t^2s Fifth term: (2s)(-0.8ts) = -1.6ts^2 Sixth term: (2s)(4s^2) = 8s^3

Now, combine like terms:

0.064t^3 - 0.32t^2s + 1.6ts^2 + 0.32t^2s - 1.6ts^2 + 8s^3

The terms "-0.32t^2s" and "0.32t^2s" cancel each other out.

Now, simplify the expression:

0.064t^3 - 1.6ts^2 + 8s^3

So, the product of (0.4t+2s) and (0.16t^2-0.8ts+4s^2) is:

0.064t^3 - 1.6ts^2 + 8s^3