Question

(3n + 2p)2 = (5a + 2b)3 = (2m – 3n)3 =8y3 + 27 =​

Answer 1

Ответ:1) 6n + 4 p

2) 15a+6b

3) 6m-9n

4) (2у+9) (4у^2-18у+81)

Объяснение:

Answer 2

It looks like you've provided a set of equations, and you'd like to solve for the variables n, p, a, b, m, and y. Let's solve these equations step by step.

1. (3n + 2p)^2 = 8y^3 + 27:

We can simplify this equation by first noticing that 8y^3 + 27 can be written as (2y)^3 + 3^3, which is a sum of cubes. We can use the sum of cubes formula:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

In our equation:

(3n + 2p)^2 = (2y)^3 + 3^3

We can rewrite it as:

(3n + 2p)^2 = (2y + 3)(4y^2 - 6y + 9)

Now, we need to solve this equation for n and p:

3n + 2p = ±√((2y + 3)(4y^2 - 6y + 9))

2. (5a + 2b)^3 = 8y^3 + 27:

We can use the same strategy here as we did in the first equation:

(5a + 2b)^3 = (2y)^3 + 3^3

(5a + 2b)^3 = (2y + 3)(4y^2 - 6y + 9)

Now, we need to solve this equation for a and b:

5a + 2b = ±√((2y + 3)(4y^2 - 6y + 9))

3. (2m - 3n)^3 = 8y^3 + 27:

Again, we'll use the same strategy:

(2m - 3n)^3 = (2y)^3 + 3^3

(2m - 3n)^3 = (2y + 3)(4y^2 - 6y + 9)

Now, we need to solve this equation for m and n:

2m - 3n = ±√((2y + 3)(4y^2 - 6y + 9))

Now, you have three equations, and you can solve for n, p, a, b, m, and y by substituting the right-hand side with the expressions involving y and solving for the respective variables. The solutions may involve complex numbers or multiple possible values depending on the specific values of y.