Question

(x+4)×x=96 1/2×(x+4)×x=96

Answer 1

(x+4)×x=96

x^2+4x

x^2+4x-96=0

(x-8)(x+12)=0

x-8=0

x+12=0

x=8

x=-12

1/2×(x+4)×x=96

1(x+4)*x=96

2

(x+4)*x=96

2

x^2+4x=96

2

2(x^2+4x)=2*96

2

x^2+4x=2*96

x^2+4x=192

x^2+4x-192=0

(x-12)(x+16)=0

x-12=0

x+16=0

x=12

x=-16

Вот это x^2 икс во второй степени если что

Answer 2

It appears that you have two equations, but you've written them in slightly different forms. Let's solve both equations:

Equation 1: (x + 4) × x = 96

To solve this equation, you can first expand it:

x^2 + 4x = 96

Now, let's move all the terms to one side to set the equation equal to zero:

x^2 + 4x - 96 = 0

Now, we can solve this quadratic equation. You can either factor it or use the quadratic formula:

Factorization:

(x + 12)(x - 8) = 0

Setting each factor equal to zero:

x + 12 = 0 --> x = -12 x - 8 = 0 --> x = 8

So, there are two solutions: x = -12 and x = 8.

Equation 2: 1/2 × (x + 4) × x = 96

To solve this equation, you can first simplify it by multiplying both sides by 2 to get rid of the fraction:

(x + 4) × x = 192

Now, it's the same as the first equation we solved. We already solved it, and the solutions are x = -12 and x = 8.

Therefore, the solutions to both equations are x = -12 and x = 8.