Question

Loq3 x=3 loq3 4+loq3 5-3 loq3 2-loq3 8?

Answer 1

Ответ: 5

Объяснение:

logx=log64+log5-log8-log8

logx=log64*5-2log8

logx=log64*5-log64

log3 x=log3 64*5/64

log3 x=log3 5,  x=5

Answer 2

It seems like you want to calculate the value of the expression:

log3(4) + log3(5) - 3*log3(2) - log3(8)

Let's break this down step by step:

1. log3(4) is the exponent to which 3 must be raised to get 4. In other words, 3^x = 4. Solving for x, we get x = 2. So, log3(4) = 2.

2. log3(5) is the exponent to which 3 must be raised to get 5. So, log3(5) = 5 (since 3^5 = 243 is the closest power of 3 to 5).

3. log3(2) is the exponent to which 3 must be raised to get 2. In other words, 3^x = 2. This means x is the square root of 2, which is an irrational number. So, log3(2) is an irrational number.

4. log3(8) is the exponent to which 3 must be raised to get 8. In other words, 3^x = 8. Solving for x, we get x = 3. So, log3(8) = 3.

Now, plug these values back into the expression:

2 + 5 - 3*irrational - 3

Since we don't know the exact value of the irrational number, we can't simplify it further. So, the result is:

2 + 5 - 3*irrational - 3

This is the simplified expression, and it can't be further simplified without knowing the value of the irrational number.