Question

1)1/6x<52)1-3x< или =03)5(у-1/2)-4,6>3у+1​

Answer 1

Ответ:

$1) \frac{1}{6} x < 5 \\ x < 5 \div \frac{1}{6} \\ x < 5 \times \frac{6}{1} \\ x < 30$

$2)1 - 3x \leqslant 0 \\ - 3x \leqslant - 1 \\ x \geqslant \frac{ - 1}{ - 3} \\ x \geqslant \frac{1}{3}$

$3)5(y - \frac{1}{2} ) - 4.6 > 3y + 1 \\ 5y - \frac{5}{2} - 4. 6> 3y + 1 \\ 5y - 3y > 1 + \frac{5}{2} + 4.6 \\ 2y > 1 + 2.5 + 4.6 \\ 2y > 8.1 \\ y > \frac{8.1}{2} \\ y > 4.05$

Объяснение:

Розв'язання в формулах, а остаточна відповідь на фото з малюнком.

Answer 2

Sure, let's solve these inequalities step by step:

1. $\frac{1}{6}x < 5$

To solve this, we can multiply both sides by 6 (remembering to reverse the inequality sign if you multiply or divide by a negative number):

$x < 30$

2. $1 - 3x \leq 0$

First, let's find the value of x when the left side is equal to 0:

$1 - 3x = 0$

$3x = 1$

$x = \frac{1}{3}$

Now, we know that the inequality is true for all values of x less than or equal to $\frac{1}{3}$. So the solution is:

$x \leq \frac{1}{3}$

3. $5(y - \frac{1}{2}) - 4.6 > 3y + 1$

Let's simplify the inequality step by step:

$5y - \frac{5}{2} - 4.6 > 3y + 1$

Combine like terms:

$5y - 9.6 > 3y + 1$

Subtract 3y from both sides:

$2y - 9.6 > 1$

Add 9.6 to both sides:

$2y > 10.6$

Finally, divide by 2:

$y > 5.3$

So, the solution is $y > 5.3$.