Question

M^(2)n+1,8mn^(2)-0,9m^(2)n+0,2mn^(2)+99 при m=-1,n=10

Answer 1

m²n + 1,8mn² - 0,9m²n +0,2mn² + 99 = 0,1m²n + 2mn² + 99

m = - 1  ;  n = 10

0,1 * (- 1)² * 10 + 2 * (- 1) * 10² + 99 = 1 - 200 + 99 = 100 - 200 = - 100

Answer 2

Ответ:

= 0,1m^(2)n+2mn^(2)+99= 0.1*1*10-2*100+99=1-200+99= -100

Объяснение:

Answer 3

To evaluate the expression $M^{2}n + 8mn^{2} - 0.9M^{2}n + 0.2Mn^{2} + 99$ when $M = -1$ and $n = 10$, we substitute these values into the expression and perform the calculations step by step:

1. Substitute $M = -1$ and $n = 10$ into $M^{2}n$: $(-1)^{2} \times 10 = 1 \times 10 = 10$

2. Substitute $M = -1$ and $n = 10$ into $8mn^{2}$: $8 \times (-1) \times 10^{2} = 8 \times (-1) \times 100 = -800$

3. Substitute $M = -1$ and $n = 10$ into $-0.9M^{2}n$: $-0.9 \times (-1)^{2} \times 10 = -0.9 \times 1 \times 10 = -9$

4. Substitute $M = -1$ and $n = 10$ into $0.2Mn^{2}$: $0.2 \times (-1) \times 10^{2} = 0.2 \times (-1) \times 100 = -20$

5. Substitute $M = -1$ and $n = 10$ into the constant term $99$: $99$

Now, add up all the values calculated in steps 1 to 5: $10 - 800 - 9 - 20 + 99 = -720$

Therefore, when $M = -1$ and $n = 10$, the expression $M^{2}n + 8mn^{2} - 0.9M^{2}n + 0.2Mn^{2} + 99$ evaluates to $-720$.