Question

(х-8)²-(х²-20х)=??????​

Answer 1

Ответ:

(x-8)²-(x²-20x)=x²-16х+64-х²+20х=4х+64

Answer 2

Let's simplify the expression $(x - 8)^2 - (x^2 - 20x)$ step by step:

Expanding the square $(x - 8)^2$, we get $x^2 - 16x + 64$.

So the expression becomes:

$x^2 - 16x + 64 - (x^2 - 20x)$

Next, distribute the negative sign through the parentheses:

$x^2 - 16x + 64 - x^2 + 20x$

Now, combine like terms:

$-16x + 20x + 64$

$4x + 64$

So, $(x - 8)^2 - (x^2 - 20x) = 4x + 64$.