Question

3√8-2√12-√20/3√18-2√27-√45

Answer 1

Смотри.....................

Answer 2

To simplify the expression:

(3√8 - 2√12 - √20) / (3√18 - 2√27 - √45)

First, let's simplify the radicals in the numerator and denominator:

Numerator: 3√8 = 3√(2^3) = 2√2 2√12 = 2√(2^2 * 3) = 4√3 √20 = √(2^2 * 5) = 2√5

So, the numerator becomes:

(2√2 - 4√3 - 2√5)

Denominator: 3√18 = 3√(2 * 3^2) = 6√2 2√27 = 2√(3^3) = 6√3 √45 = √(3^2 * 5) = 3√5

So, the denominator becomes:

(6√2 - 6√3 - 3√5)

Now, the expression becomes:

(2√2 - 4√3 - 2√5) / (6√2 - 6√3 - 3√5)

Now, you can factor out common terms in the numerator and denominator:

2(√2 - 2√3 - √5) / 3(2√2 - 2√3 - √5)

Now, you can cancel out the common factor of 2 in the numerator and denominator:

(√2 - 2√3 - √5) / (3√2 - 3√3 - 3√5)

Now, you have simplified the expression as much as possible.