Question

1) 3(х-4)+5(2х-1)= 2) 3х²+6х+7=0

Answer 1

Ответ:

1) 13х-17

2) нет корней

Объяснение:

1) ...=3х-12+10х-5=13х-17

2) $D=6^{2} -4*3*7=36-84=-48$

уравнение не имеет корней

Answer 2

надеюсь, хоть как-то поможет

Answer 3

Let's solve each equation:

1. 3(x - 4) + 5(2x - 1)

First, distribute the numbers outside the parentheses:

3x - 12 + 10x - 5

Now, combine like terms:

(3x + 10x) + (-12 - 5) = 13x - 17

So, the simplified equation is:

13x - 17

2. 3x^2 + 6x + 7 = 0

This is a quadratic equation. We can use the quadratic formula to solve for x:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 3, b = 6, and c = 7. Plug these values into the quadratic formula:

x = (-6 ± √(6^2 - 4 * 3 * 7)) / (2 * 3)

x = (-6 ± √(36 - 84)) / 6

x = (-6 ± √(-48)) / 6

Now, you have the square root of a negative number, which means the solutions will be complex numbers. To simplify further:

x = (-6 ± √(16 * -3)) / 6

x = (-6 ± 4√(-3)) / 6

x = (-3 ± 2√(-3)) / 3

So, the solutions for the quadratic equation are:

x = (-3 + 2√(-3)) / 3 and x = (-3 - 2√(-3)) / 3

These solutions are complex numbers because they involve the square root of a negative number.