Question

(2x+6)(7-4x)=(2-x)(8x-1)+15

Answer 1

Решение и ответ - на приложенном фото

Answer 2

Ответ:

х=1целая 2/27

Объяснение:

(2х+6)(7–4х)=(2–х)(8х–1)+15

14х–8х²+42–24х=16х–2–8х²+х+15

–10х–8х²–16х+8х²–х=13–42

–27х= –29

х=29/27

х=1целая 2/27

Answer 3

To solve the equation (2x+6)(7-4x) = (2-x)(8x-1) + 15, you can follow these steps:

1. Expand both sides of the equation:

   (2x+6)(7-4x) = (2-x)(8x-1) + 15

   Expand the left side:

   14x - 8x^2 + 42 - 24x = (2-x)(8x-1) + 15

   14x - 8x^2 + 42 - 24x = 16x^2 - 9x - 15 + 15

2. Simplify and collect like terms:

   Combine like terms on both sides of the equation:

   -8x^2 - 10x + 42 = 16x^2 - 9x

3. Move all terms to one side of the equation to set it equal to zero:

   -8x^2 - 10x + 42 - 16x^2 + 9x = 0

4. Combine like terms:

   -24x^2 - x + 42 = 0

5. Now, you have a quadratic equation. To solve it, you can use the quadratic formula:

   x = (-b ± √(b² - 4ac)) / (2a)

   In this case, a = -24, b = -1, and c = 42.

   x = (1 ± √((-1)² - 4(-24)(42))) / (2(-24))

   x = (1 ± √(1 + 4032)) / (-48)

   x = (1 ± √4033) / (-48)

So, the solutions for the equation are:

x = (1 + √4033) / (-48) and x = (1 - √4033) / (-48).