Question

B) I - 2x+3 + 3 + 9x + 8 < 0;​

Answer 1

Пошаговое объяснение:

15+7x<0

7x< -15

x<-15

7

Answer 2

To solve the inequality $I - 2x + 3 + 3 + 9x + 8 < 0$, you need to combine like terms and isolate (x\ on one side of the inequality sign. Here are the steps:

$I - 2x + 3 + 3 + 9x + 8 < 0$

Combine like terms:

$I + 11x + 14 < 0$

Now, to isolate (x, you can subtract 14 from both sides of the inequality:

$I + 11x + 14 - 14 < 0 - 14$

$I + 11x < -14$

Finally, divide both sides by 11 to solve for (x:

$\frac{I + 11x}{11} < \frac{-14}{11}$

$x < \frac{-14}{11} - \frac{I}{11}$

So, the solution to the inequality is:

$x < \frac{-14}{11} - \frac{I}{11}$