Question

Cos105°+cos75°. Hsvsvsvndnxnndbdbxbbxbxbcbbxbx

Answer 1

Ответ:

Объяснение:

!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

cos(105°) and cos(75°) can be calculated using trigonometric ratios.

We know that the cosine function relates the angle measurement to the ratio of the adjacent side length to the hypotenuse side length of a right triangle.

To calculate cos(105°), we need to find the values of the adjacent and hypotenuse sides of a right triangle with a 105° angle. Since cosine is positive in the second quadrant, we consider a right triangle in that quadrant.

Let's assume that the adjacent side is represented by "a" and the hypotenuse side is represented by "h".

Using the Pythagorean theorem, we can find the value of the opposite side:

sin(105°) = opposite/hypotenuse sin(105°) = a/h

Since sine is positive in the second quadrant, we take the positive square root of 1 - sin^2(105°) to find the value of the adjacent side:

a = sqrt(h^2 - sin^2(105°))

Now, we can substitute this value of "a" into the cosine ratio:

cos(105°) = a/h cos(105°) = sqrt(h^2 - sin^2(105°))/h

Similarly, to calculate cos(75°), we follow the same steps, but this time considering a right triangle in the first quadrant where cosine is positive.

Let's assume that the adjacent side is represented by "b" and the hypotenuse side is represented by "k".

Using the Pythagorean theorem, we can find the value of the opposite side:

sin(75°) = opposite/hypotenuse sin(75°) = b/k

Since sine is positive in the first quadrant, we take the positive square root of 1 - sin^2(75°) to find the value of the adjacent side:

b = sqrt(k^2 - sin^2(75°))

Now, we can substitute this value of "b" into the cosine ratio:

cos(75°) = b/k cos(75°) = sqrt(k^2 - sin^2(75°))/k

By plugging in the numerical values for "h" and "k" from the above equations, we can calculate the exact values of cos(105°) and cos(75°).