
Помогите пожалуйста: Знайти множину розвязків система нерівностей {3x ≤ 7 {2+x ≤ 5
Смотреть ответ olgaua64 olgaua64 Відповідь: хє(-inf; 2⅓] Пояснення: {3x ≤ 7 {2+x ≤ 5 {х≤7/3 {х≤5-2 {х≤2⅓ {х≤3 /////////////////2⅓_____3________ ///////////////////////////////3_________ хє(-inf; 2⅓] Новые вопросы в Алгебра Дано функцію y=x³-ax²+4x-5. При якому значенні параметра a кут нахилу дотичної, проведеної до графіка цієї функції в точці x0=1, дорівнює 45°?Буду дуж … е вдячен за розв'язок РЕШИТЕ 22 и 23 ОЧЕНЬ СРОЧНО, ЗАРАНЕЕ СПАСИБО cos3(альфа)- cos(альфа)/sin3(альфа)+sin(альфа) РЕШИТЕ 13 И 14 ОЧЕНЬ НАДО, ЗАРАНЕЕ СПАСИБО 2 Знайдіть к, якщо пряма у = kx + 3 утворює з додатним напрямом осі Ох кут 135°. Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Ответы на вопрос

System of Inequalities
To find the solution set for the system of inequalities {3x+≤+7 and {2+x+≤+5, we can solve each inequality separately and then find the intersection of their solution sets.
First inequality: {3x+≤+7
To solve this inequality, we need to isolate x. We can do this by subtracting 7 from both sides: 3x ≤ 7 - Subtract 7 from both sides x ≤ 7/3 - Divide both sides by 3
Second inequality: {2+x+≤+5
To solve this inequality, we need to isolate x. We can do this by subtracting 2 from both sides: x + 2 ≤ 5 - Subtract 2 from both sides x ≤ 5 - 2 x ≤ 3
Now, we need to find the intersection of the solution sets for both inequalities. Since both inequalities have x ≤ a certain value, the solution set will be the values of x that satisfy both inequalities.
The intersection of the solution sets is the set of values that are less than or equal to both 7/3 and 3. In other words, the solution set is the set of values that are less than or equal to the smaller of the two values.
Therefore, the solution set for the system of inequalities {3x+≤+7 and {2+x+≤+5 is x ≤ 2⅓.
Tangent Line Slope
Given the function y = x³ - ax² + 4x - 5, we need to find the value of the parameter a for which the slope of the tangent line to the graph of this function at the point x0 = 1 is 45°.
To find the slope of the tangent line at a given point, we need to find the derivative of the function and evaluate it at that point.
The derivative of the function y = x³ - ax² + 4x - 5 is given by: dy/dx = 3x² - 2ax + 4
To find the slope of the tangent line at x = x0 = 1, we substitute x = 1 into the derivative: dy/dx = 3(1)² - 2a(1) + 4 dy/dx = 3 - 2a + 4 dy/dx = 7 - 2a
We want the slope of the tangent line to be


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