Question

В треугольниках ABC и A1 B1 C1 медианы АМ и A1 M1 равны BC равно B1 C1 и угол АМB равен углу А1 M1 B1 Докажите что треугольник ABC равен треугольнику A1 B1 C1 пж пж пж пж пж пж пж пж пж пж пж пж пж пж пж пж пж​

Answer 1

Ответ:

A6

Объяснение:

если я не прав то исправте

Answer 2

Для начала давайте переведем ваш запрос на английский язык:

"Answer in detail. In triangles ABC and A1B1C1, the medians AM and A1M1 are equal, BC is equal to B1C1, and angle AMB is equal to angle A1M1B1. Prove that triangle ABC is congruent to triangle A1B1C1."

To prove that triangle ABC is congruent to triangle A1B1C1, we can use the Side-Angle-Side (SAS) congruence criterion. According to this criterion, if two triangles have two sides and the included angle of one triangle equal to the corresponding sides and included angle of the other triangle, then the triangles are congruent.

Let's break down the proof step by step:

Step 1: Given that medians AM and A1M1 are equal, we can write: AM = A1M1 (Given)

Step 2: Given that BC is equal to B1C1, we can write: BC = B1C1 (Given)

Step 3: Given that angle AMB is equal to angle A1M1B1, we can write: ∠AMB = ∠A1M1B1 (Given)

Step 4: Now, we need to prove that triangle ABC is congruent to triangle A1B1C1 using the SAS criterion.

Step 5: We already have two sides and the included angle equal: AM = A1M1 (Step 1) BC = B1C1 (Step 2) ∠AMB = ∠A1M1B1 (Step 3)

Step 6: By the SAS criterion, we can conclude that triangle ABC is congruent to triangle A1B1C1.

Hence, we have proven that triangle ABC is congruent to triangle A1B1C1 based on the given information.