Question

(9:10-1:8m^7)^2многочлен в стандартном виде

Answer 1

Ответ:

Объяснение:

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Answer 2

Polynomial in Standard Form

To express the polynomial \((9x^10 - 1x^8)^2\) in standard form, we need to expand the expression and combine like terms.

Expanding the Polynomial

First, we'll expand the given expression using the formula \((a - b)^2 = a^2 - 2ab + b^2\).

Expanding \((9x^10 - 1x^8)^2\): \[ (9x^{10} - 1x^8)^2 = (9x^{10})^2 - 2(9x^{10})(1x^8) + (1x^8)^2 \]

Simplifying the Terms

Now, let's simplify the terms: \[ (9x^{10})^2 = 81x^{20} \] \[ 2(9x^{10})(1x^8) = 18x^{18} \] \[ (1x^8)^2 = x^{16} \]

Combining Like Terms

Finally, combining the terms, we get the polynomial in standard form: \[ 81x^{20} - 18x^{18} + x^{16} \]

So, the polynomial \((9x^{10} - 1x^8)^2\) in standard form is \(81x^{20} - 18x^{18} + x^{16}\).