Question

78z^2+5=(6z+1)(13z+6)

Answer 1

Ответ:

$\frac{-1}{49}$

Объяснение:

$78z^{2} +5=78z^{2}+ 36z+13z+6\\5=36z+13z+6\\\5=49z+6\\-49z=6-5\\-49z=1\\z=-\frac{1}{49}$

Answer 2

To solve the given equation, we can start by expanding the right side of the equation:

(6z + 1)(13z + 6) = 78z^2 + 36z + 13z + 6

Simplifying further:

= 78z^2 + (36z + 13z) + 6 = 78z^2 + 49z + 6

Now we can set this expression equal to the left side of the equation:

78z^2 + 49z + 6 = 78z^2 + 5

Subtracting 78z^2 from both sides:

49z + 6 = 5

Subtracting 6 from both sides:

49z = -1

Finally, dividing both sides by 49:

z = -1/49

Therefore, the solution to the equation 78z^2 + 5 = (6z + 1)(13z + 6) is z = -1/49.