Question

Решите уравнение: 2x2−50=0

Answer 1

Ответ:

2*х^2=50 или х^2=25 или х1=5, х2=-5. Все просто и успехов в науках.

Answer 2

Ответ:

Если 2х²-50=0, то:

D=(-50)²-4*2*0=(-50)²

x1=50+√(-50)²/2*2=50+50/4=100/4=25

x2=50-√(-50)²/2*2=50-50/4=0/4=0

Answer 3

I can help you solve the equation.

Here are the steps to solve the equation:

- First, we need to move the constant term to the right side of the equation by adding 50 to both sides. This gives us:

$$2x^2 = 50$$

- Next, we need to divide both sides by 2 to isolate $x^2$. This gives us:

$$x^2 = 25$$

- Then, we need to take the square root of both sides to find the possible values of $x$. This gives us:

$$x = \pm \sqrt{25}$$

- Finally, we need to simplify the square root and write the solution as a set of two numbers. This gives us:

$$x = \pm 5$$

$$\{x \mid x = -5 \text{ or } x = 5\}$$

This is the solution set of the equation. You can check it by plugging in the values of $x$ into the original equation and verifying that they make it true. For more information on how to solve quadratic equations, you can visit [this website](https://www.kontrolnaya-rabota.ru/s/equal-one/any-uravnenie/e/2_x_2_minus_pyat_desyat_ravno_nol/). I hope this helps.