Question

Розв'язати рівняння (х+3)2 - 2 (х+3) - 8 = 0.​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

Ответ:

х = -5 ; х =1

Объяснение:

(х+3)² - 2*(х+3) - 8 = 0.​

1 способ:

Пусть х+3=у, тогда

у²-2у-8=0

D = (-2)²-4*1*(-8) = 4+32 = 36 = 6²

y₁₂ = (2±6)/(2*1)

y₁ = 4 ; y₂ = -2

Вернёмся к замене:

Если y = 4, тогда х+3 = 4 ⇔ х = 1

Если y = -2, тогда х+3 = -2 ⇔ х = -5

2 способ:

х²+6х+9-2х-6-8 = 0

х²+4х-5 = 0

D = 4²-4*1*(-5) = 16+20 = 36 = 6²

х₁₂ = (-4±6)/(2*1)

х₁ = 1 ; х₂ = -5

Answer 3

I can help you solve this equation. First, let's rewrite it in a simpler form:

$$(x+3)^2 - 2(x+3) - 8 = 0$$

Next, let's expand the squared term and simplify:

$$x^2 + 6x + 9 - 2x - 6 - 8 = 0$$ $$x^2 + 4x - 5 = 0$$

Now, we can use the quadratic formula to find the values of $x$ that satisfy the equation:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

In this case, $a = 1$, $b = 4$, and $c = -5$. Plugging these values into the formula, we get:

$$x = \frac{-4 \pm \sqrt{4^2 - 4(1)(-5)}}{2(1)}$$ $$x = \frac{-4 \pm \sqrt{36}}{2}$$ $$x = \frac{-4 \pm 6}{2}$$

Therefore, the two possible solutions are:

$$x = \frac{-4 + 6}{2} = 1$$ $$x = \frac{-4 - 6}{2} = -5$$

We can check that these values satisfy the original equation by plugging them back in. I hope this helps you understand how to solve this equation.Ответь+подробно.++Розв'язати+рівняння+(х+3)2 -+2+(х+3)+-+8+=+0.​+