Question

1) В треугольникеАВС АВ>ВС>АС. Найти<А,<В,<С, если один из углов 110°, а другой 60°. помогите пж​

Answer 1

Согласно свойству всех треугольников, сумма углов равна 180°.
Зная два угла можно легко найти третий: 180° - (110°+60°) = 10°.
Теперь, согласно условию AB>BC>AC, имеем, что <AB= 110°, <BC= 60°, <AC=10°

Answer 2

I can help you with your geometry question.

To find the angles of a triangle, you need to use the fact that the sum of the angles is 180°. If one angle is 110° and another is 60°, then the third angle is 180° - 110° - 60° = 10°. Therefore, the angles are 110°, 60°, and 10°.

However, you also need to consider the order of the angles. Since the sides of the triangle are in the order AB > BC > AC, the angles opposite to them are also in the same order. That means the angle opposite to AB is the largest, the angle opposite to BC is the smallest, and the angle opposite to AC is the middle one. So, the angles are:

∠A = 10° ∠B = 110° ∠C = 60°

I hope this helps you understand the problem. If you need more help, you can check out this web page that explains how to find the angles of a triangle.

: https://class.rambler.ru/temy-gdz/1-v-treugolnike-avs-av-vs-as-naydite-a-b-c-esli-kontrolnye-raboty-variant-2-k-4-geometriya-7-klass-ziv-gdz-29970.htm