Question

Доказать неравенство. 15x+(12x-1)(3x+1)<1+(6x+2) в квадрате умоляю срочно!!!

Answer 1

Ответ:

Вот держи!!

Объяснение:

Вот держи!!

Answer 2

Solving the Inequality

To solve the given inequality 15x(12x-1)(3x+1) < 1 + (6x+2)^2, we can follow these steps:

1. Expand and simplify the expression on both sides of the inequality. 2. Solve for the values of x that satisfy the inequality.

Step 1: Expand and Simplify

Let's start by expanding and simplifying the expression on both sides of the inequality.

The given inequality is: 15x(12x-1)(3x+1) < 1 + (6x+2)^2

Expanding the right-hand side: 1 + (6x+2)^2 = 1 + (36x^2 + 24x + 4) = 36x^2 + 24x + 5

So, the inequality becomes: 15x(12x-1)(3x+1) < 36x^2 + 24x + 5

Step 2: Solve for x

Now, we need to solve for the values of x that satisfy the inequality.

To do this, we can subtract the right-hand side from the left-hand side and then solve the resulting quadratic inequality.

The resulting inequality is: 15x(12x-1)(3x+1) - (36x^2 + 24x + 5) < 0

After solving the inequality, we can find the intervals of x that satisfy the inequality.

Let's proceed with solving the inequality and finding the intervals of x that satisfy it.