Question

2 багета и 5 булок весят на 480 г больше 1 багета. но весят на 40г меньше 3 багетов

Answer 1

Ответ:

вы не написали, что найти, но

багет=260, а булка=44

Объяснение:

пусть х-багет, а у- булка, тогда

2х+5у=480+х и 2х+5у=3х-40

х=480-5у подставим в 2 уравнение

2*(480-5у)+5у=3(480-5у)-40

-480+5у+5у=-40

10у=440

у=44, следовательно х=480-220=260

Answer 2

Problem Statement:

The problem states that 2 baguettes and 5 rolls weigh 480g more than 1 baguette, but they weigh 40g less than 3 baguettes.

Solution:

Let's assume the weight of one baguette is x grams.

According to the problem, 2 baguettes and 5 rolls weigh 480g more than 1 baguette. This can be expressed as:

2x + 5y = x + 480g ---(Equation 1)

where y represents the weight of one roll.

Similarly, it is given that 2 baguettes and 5 rolls weigh 40g less than 3 baguettes. This can be expressed as:

2x + 5y = 3x - 40g ---(Equation 2)

To solve this system of equations, we can use substitution or elimination method. Let's use the elimination method.

Subtracting Equation 1 from Equation 2, we get:

(2x + 5y) - (x + 480g) = (3x - 40g) - (2x + 5y)

x - 480g = x - 40g - 5y

-480g = -40g - 5y

-440g = -5y

Dividing both sides by -5, we get:

88g = y

Now, we can substitute the value of y back into Equation 1 to find the weight of one baguette:

2x + 5(88g) = x + 480g

2x + 440g = x + 480g

x = 40g

Therefore, the weight of one baguette is 40g.

Answer:

According to the given information, one baguette weighs 40g.