Question

Знайдіть значення аргументу, при якому значення функції: у = -3х + 2 дорівнює -7; 0; 5

Answer 1

Ответ:

-3 ; -0.6 ; 1

Объяснение:

y = -3x + 2

-7 = -3x + 2

-3x = 2 - (-7)

-3x = 9

x = 9 : (-3)

x = -3

0= -3x + 2

-3x = 2 -0

x = 2 : ( -3)

x ≈ - 0,6

5 = -3x + 2

-3x =2-5

-3x = -3

x = -3 : (-3)

x = 1

Answer 2

Finding the Value of the Argument for a Given Function

To find the value of the argument at which the value of the function \( u = -3x + 2 \) equals -7, 0, and 5, we can solve for the value of \( x \) in each case.

1. When \( u = -7 \): - Substitute \( u = -7 \) into the function: \[ -3x + 2 = -7 \] - Solve for \( x \): \[ -3x = -7 - 2 \] \[ -3x = -9 \] \[ x = \frac{-9}{-3} \] \[ x = 3 \]

2. When \( u = 0 \): - Substitute \( u = 0 \) into the function: \[ -3x + 2 = 0 \] - Solve for \( x \): \[ -3x = -2 \] \[ x = \frac{-2}{-3} \] \[ x \approx 0.67 \]

3. When \( u = 5 \): - Substitute \( u = 5 \) into the function: \[ -3x + 2 = 5 \] - Solve for \( x \): \[ -3x = 5 - 2 \] \[ -3x = 3 \] \[ x = \frac{3}{-3} \] \[ x = -1 \]

Therefore, the values of \( x \) at which the function \( u = -3x + 2 \) equals -7, 0, and 5 are: - \( x = 3 \) when \( u = -7 \) - \( x \approx 0.67 \) when \( u = 0 \) - \( x = -1 \) when \( u = 5 \).

Conclusion

The values of the argument \( x \) for which the function \( u = -3x + 2 \) equals -7, 0, and 5 are 3, approximately 0.67, and -1, respectively.