Question

A) x(x + 2) = 2x + 2; B) x(5x + 3) = x(x+3)+32;​

Answer 1

Ответ:

1фото это ответ на А

2 фото ответ на В

Answer 2

Let's solve the given equations step by step:

A) x(x + 2) = 2x + 2

Expanding the left side of the equation: x^2 + 2x = 2x + 2

Now, let's move all the terms to one side of the equation: x^2 + 2x - 2x - 2 = 0

Combining like terms: x^2 - 2 = 0

Adding 2 to both sides: x^2 = 2

Taking the square root of both sides (considering both positive and negative roots): x = ±√2

Therefore, the solutions to equation A) are x = √2 and x = -√2.

B) x(5x + 3) = x(x + 3) + 32

Expanding the left side of the equation: 5x^2 + 3x = x^2 + 3x + 32

Now, let's move all the terms to one side of the equation: 5x^2 + 3x - x^2 - 3x - 32 = 0

Combining like terms: 4x^2 - 32 = 0

Dividing both sides by 4: x^2 - 8 = 0

Adding 8 to both sides: x^2 = 8

Taking the square root of both sides (considering both positive and negative roots): x = ±√8

Simplifying the square root: x = ±2√2

Therefore, the solutions to equation B) are x = 2√2 and x = -2√2.