Question

Запишіть у вигляді многочлена: 1) 7m(m³-8m²+9) 2) (3m-4n) (5m+8n) 3) (y+3) (y²+y-6)

Answer 1

Ответ:

$1) 7m(m^3-8m^2+9)= 7m ^4-56m^3+63m\\2)(3m-4n)(5m+8n)=15m^2+24mn-20mn-32n^2= 15m^2+4mn-32n^2\\3) (y+3)(y ^2+y -6)=y^3+y^2-6y+3 y^2-18=y^3+4y^2 -3y -18$

Answer 2

Ответ:

$7m( {m}^{3 } - 8 {m}^{2} + 9) = 7 {m}^{4} - 56 {m}^{3} + 63m$

$(3m - 4n)(5m + 8n) = 15 {m}^{2} + 24mn - 20mn - 32 {n}^{2} = 15 {m}^{2} 4mn - 32 {n}^{2}$

$(y + 3)( {y}^{2} + y - 6) = {y}^{3} + {y}^{2} - 6y + 3 {y}^{2} + 3y - 18 = {y}^{3} + 3 {y}^{4} - 24 + 3y$

держи:) удачи с уроками

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Answer 3

1. 7m(m³-8m²+9) can be written as: 7m^4 - 56m^3 + 63m

2. (3m-4n) (5m+8n) can be expanded using the distributive property: 15m^2 - 20mn + 24mn - 32n^2

Simplifying further, we get: 15m^2 + 4mn - 32n^2

3. (y+3) (y²+y-6) can be expanded as: y³ + y² - 6y + 3y² + 3y - 18

Simplifying further, we get: y³ + 4y² - 3y - 18