Question

0,5х²-8≥0 СРОЧНООООООО

Answer 1

Ответ:

$0.5 {x}^{2} - 8 \geqslant 0$

$\frac{1}{2} {x}^{2} - 8 \geqslant 0$

$\frac{1}{2} {x}^{2} \geqslant 8| \times 2$

${x}^{2} \geqslant 16$

$\sqrt{ {x}^{2} } \geqslant \sqrt{16}$

$|x| \geqslant 4$

$x \geqslant 4.x \geqslant 0 \\ - x \geqslant 4.x < 0$

$x\in[4, +\infty> \\ x \leqslant - 4.x < 0$

$x\in[4, +\infty> \\ x\in$

$x\in$

Answer 2

To solve the inequality 0.5x² - 8 ≥ 0, we can follow these steps:

Step 1: Move the constant term to the other side of the inequality: 0.5x² ≥ 8

Step 2: Multiply both sides of the inequality by 2 to eliminate the decimal: x² ≥ 16

Step 3: Take the square root of both sides of the inequality. Remember to consider both the positive and negative square roots: x ≥ ±√16

Step 4: Simplify the square root: x ≥ ±4

So, the solution to the inequality 0.5x² - 8 ≥ 0 is x ≥ 4 or x ≤ -4.