Question

4x^2 - 4x + 1 = 0 x = ?

Answer 1

4х^2-4х+1=0
Решение:
(2х-1)^2=0
2х-1=0
2х=1
Ответ:х=1/2

Answer 2

To find the value of x in the equation 4x^2 - 4x + 1 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 4, b = -4, and c = 1.

Substituting these values into the quadratic formula, we have:

x = (-(-4) ± √((-4)^2 - 4 * 4 * 1)) / (2 * 4) = (4 ± √(16 - 16)) / 8 = (4 ± √0) / 8

Since the discriminant (√(b^2 - 4ac)) is 0, we will have repeated roots.

Therefore, the solutions are:

x = (4 + 0) / 8 = 4 / 8 = 1/2

and

x = (4 - 0) / 8 = 4 / 8 = 1/2

So, the value of x in the equation 4x^2 - 4x + 1 = 0 is x = 1/2.