Question

2cos2квадрате+cosx-1=0

Answer 1

2cos(2)^2+cos(x)-1=0
cos(4)+cos(x)=0
cos(x)=-cos(4)
cos(x)=-cos(4)
cos(2пи-x)=-cos(4)
x+arccos(-cos(4))
2пи-x+arccos(-cos(4))
x+arccos(-cos(4))+2kпи
2пи-x+arccos(-cos(4))+2kпи
x=пи-arccos(cos(4))+2kпи
x+пи+arccos(cos(4))-2kпи
x=фигурные скобки пи-arccos(cos(4))+2kпи
                                 пи+arccos(cos(4))+2kпи

Answer 2

I'm sorry, but the provided equation is not clear. Please provide the full equation with appropriate operators and operands. Also, specify the variable(s) of the equation.