Question

A) 22p^4 q^2/99p^ 5q б) 7a/a^2+5a в) y^2-z^2/2y+2z г) a^2-1/a^2-2a+1 /-делимпомогите пожалуйста 

Answer 1

A) 22p^4q^2  = 2*11p^4q^2 = 2q
    99p^5 q        9*11p^5 q       9p

б)   7а   =   7а       =     7     
    а²+5а    а(а+5)      а+5

в) y² -z² =   (y-z)(y+z) = y-z
    2y+2z        2(y+z)       2

г)    a² -1       =   (a-1)(a+1)  = a+1
    a² -2a+1              (a-1)²       a-1

Answer 2

а) To simplify the expression 22p^4 q^2/99p^5q, we can first cancel out any common factors in the numerator and denominator. Here, we see that both the numerator and denominator have factors of p and q, so we can cancel them out:

22p^4 q^2/99p^5q = (22/99) * (p^4/p^5) * (q^2/q)

Simplifying further, we can cancel out the p^4/p^5 and q^2/q terms:

(22/99) * (p^4/p^5) * (q^2/q) = (22/99) * (1/p) * q

Therefore, the simplified expression is (22/99) * (1/p) * q.

б) To simplify the expression 7a/a^2+5a, we need to factor the denominator. We can factor out a from the denominator to get:

7a/a^2+5a = 7a/(a(a+5))

Now, we can cancel out the common factor of a:

7a/(a(a+5)) = 7/(a+5)

Therefore, the simplified expression is 7/(a+5).

в) To simplify the expression y^2-z^2/2y+2z, we need to factor the numerator and denominator. We can use the difference of squares formula to factor the numerator:

y^2 - z^2 = (y+z)(y-z)

We can also factor out a 2 from the denominator:

2y + 2z = 2(y+z)

Now, we can simplify the expression by canceling out the common factor of y+z:

(y+z)(y-z)/2(y+z) = (y-z)/2

Therefore, the simplified expression is (y-z)/2.

г) To simplify the expression a^2-1/a^2-2a+1, we can use the difference of squares formula to factor the denominator:

a^2 - 2a + 1 = (a-1)^2

Now, we can simplify the expression by canceling out the common factor of a-1:

a^2-1/(a-1)^2 = (a+1)(a-1)/(a-1)^2

We can further simplify by canceling out the common factor of a-1 in the numerator and denominator:

(a+1)(a-1)/(a-1)^2 = (a+1)/(a-1)

Therefore, the simplified expression is (a+1)/(a-1).