Question

16x^2-56x+13=0 срочно!!

Answer 1

////////////////////////////////////

Answer 2

To solve the quadratic equation:

16x^2 - 56x + 13 = 0

we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = 16, b = -56, and c = 13.

Substituting these values into the quadratic formula, we get:

x = (-(-56) ± √((-56)^2 - 4(16)(13))) / 2(16)

Simplifying this expression, we get:

x = (56 ± √(56^2 - 4(16)(13))) / 32

x = (56 ± √2304) / 32

x = (56 ± 48) / 32

Therefore, the solutions are:

x1 = (56 + 48) / 32 = 2.25

x2 = (56 - 48) / 32 = 0.25

So the solutions to the equation 16x^2 - 56x + 13 = 0 are x1 = 2.25 and x2 = 0.25.