Question

X^(у квадраті)-2x+5(x-2)=0

Answer 1

Ответ: {-5; 2}.

Объяснение:

Х²-2х + 5(х-2)=0

Х²-2х + 5х - 10 = 0.

Х²+3х-10=0.

D=3²+4×10=49, √D = 7

X1= (-3+7)/2×1 = 2,

X2=(-3-7)/2×1=-5.

Answer 2

To solve the equation $x^{у квадраті} - 2x + 5(x - 2) = 0$, I will assume that the phrase "у квадраті" is intended to represent an exponent of 2. Therefore, the equation can be rewritten as:

$x^2 - 2x + 5(x - 2) = 0$

Expanding the equation, we have:

$x^2 - 2x + 5x - 10 = 0$

Simplifying further:

$x^2 + 3x - 10 = 0$

Now, we can solve this quadratic equation using factoring, completing the square, or the quadratic formula. Let's solve it using the quadratic formula.

The quadratic formula states that for an equation in the form of $ax^2 + bx + c = 0$, the solutions for $x$ can be found using the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

For our equation $x^2 + 3x - 10 = 0$, we have $a = 1$, $b = 3$, and $c = -10$. Substituting these values into the quadratic formula, we get:

$x = \frac{-3 \pm \sqrt{3^2 - 4(1)(-10)}}{2(1)}$

Simplifying further:

$x = \frac{-3 \pm \sqrt{9 + 40}}{2}$ $x = \frac{-3 \pm \sqrt{49}}{2}$ $x = \frac{-3 \pm 7}{2}$

This gives us two possible solutions:

1. When $x = \frac{-3 + 7}{2} = 2$
2. When $x = \frac{-3 - 7}{2} = -5$

Therefore, the solutions to the equation $x^{у квадраті} - 2x + 5(x - 2) = 0$ are $x = 2$ and $x = -5$.