Question

2(x-3)-2x^2=x-(2x+1)^2​

Answer 1

Объяснение:

2(x-3)-2x^2=x-(2x+1)^2

2×-6-2x^2=x-2x^2+4x+1

2x-6-2x^2-x+2x^2-4x-1=0

2x-6-x-4×-1=0

-3×-7=0

×=-7/3

Answer 2

Держи
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Answer 3

To solve the equation 2(x-3)-2x^2=x-(2x+1)^2, let's simplify it step by step:

First, let's expand the squared term on the right side of the equation: 2(x-3) - 2x^2 = x - (4x^2 + 4x + 1)

Next, distribute the 2 on the left side: 2x - 6 - 2x^2 = x - (4x^2 + 4x + 1)

Simplify the equation further by distributing the negative sign on the right side: 2x - 6 - 2x^2 = x - 4x^2 - 4x - 1

Combine like terms on both sides of the equation: -2x^2 + 2x - 6 = -3x^2 - 4x - 1

Now, let's gather all the terms on one side of the equation, which will give us a quadratic equation: 0 = -3x^2 - 4x - 1 + 2x^2 - 2x + 6

Combine like terms again: 0 = -x^2 - 6x + 5

To solve this quadratic equation, we can factor it or use the quadratic formula. Let's use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = -1, b = -6, and c = 5.

Substituting these values into the quadratic formula: x = (-(-6) ± √((-6)^2 - 4(-1)(5))) / (2(-1))

Simplifying: x = (6 ± √(36 + 20)) / (-2) x = (6 ± √56) / (-2) x = (6 ± 2√14) / (-2) x = (3 ± √14) / (-1)

Therefore, the solutions to the equation 2(x-3)-2x^2=x-(2x+1)^2 are: x = (3 + √14) / (-1) and x = (3 - √14) / (-1).