Question

ЭДС источника Е=21 В, его внутреннее сопротивление r=1 Ом, сопротивление резисторов R1=50Ом, R2=30Ом, сопротивление вольтометра Rv=320Ом, сопротивление амперметра Ra=5Ом. Определите показание вольтометра и амперметра.

Answer 1

без картинки не решается

хоть словами тогда опиши как соединены резисторы, куда подключен вольтметр и амперметр

Answer 2

Calculation of Voltmeter Reading (Rv)

To determine the reading of the voltmeter, we need to calculate the equivalent resistance of the circuit. The equivalent resistance can be found by adding the resistance of the voltmeter (Rv) in parallel with the resistance of the load (R1).

The formula for calculating the equivalent resistance in a parallel circuit is:

1/Req = 1/Rv + 1/R1

Substituting the given values:

1/Req = 1/320 + 1/50

Now, we can calculate the value of Req:

1/Req = 0.003125 + 0.02

1/Req = 0.023125

Taking the reciprocal of both sides:

Req = 1/0.023125

Req ≈ 43.243

Therefore, the equivalent resistance of the circuit (Req) is approximately 43.243 ohms.

To find the voltmeter reading, we can use the voltage divider rule:

Vv = (Rv / (Rv + Req)) * E

Substituting the given values:

Vv = (320 / (320 + 43.243)) * 21

Vv ≈ 15.36

Therefore, the voltmeter reading is approximately 15.36 volts.

Calculation of Ammeter Reading (Ra)

To determine the reading of the ammeter, we need to calculate the equivalent resistance of the circuit. The equivalent resistance can be found by adding the resistance of the ammeter (Ra) in series with the resistance of the load (R2).

The formula for calculating the equivalent resistance in a series circuit is:

Req = Ra + R2

Substituting the given values:

Req = 5 + 30

Req = 35

Therefore, the equivalent resistance of the circuit (Req) is 35 ohms.

To find the ammeter reading, we can use Ohm's Law:

Ia = E / Req

Substituting the given values:

Ia = 21 / 35

Ia ≈ 0.6

Therefore, the ammeter reading is approximately 0.6 amperes.

In summary, the voltmeter reading is approximately 15.36 volts, and the ammeter reading is approximately 0.6 amperes.