Question

В сеть с напряжением 220В паралельно включены две групы ламп.в одной группе 8 ламп сопротивлением 1,6*10^2 Ом каждая, в другой 10 ламп сопротивлением 2,0*10^2 Ом каждая.Определить общее сопротивление и общую силу тока.

Answer 1

Общее сопротивление в одной группе R1=8*1,6*100=1280Ом
В другой R2=10*2*100=2000Ом
Общее сопротивление R при параллельном подключении равно (R1*R2)/(R1+R2)=780,48 Ом
Общая сила тока I=U/R=220/780,48=0,28A

Answer 2

Calculation of Total Resistance and Total Current

To determine the total resistance and total current in a parallel circuit with a voltage of 220V, we need to calculate the equivalent resistance and use Ohm's Law.

Let's start by calculating the equivalent resistance of the two groups of lamps in parallel.

The first group consists of 8 lamps, each with a resistance of 1.6 * 10^2 Ohms. To find the equivalent resistance of this group, we can use the formula for resistors in parallel:

1/R_eq = 1/R1 + 1/R2 + ... + 1/Rn

where R_eq is the equivalent resistance and R1, R2, ..., Rn are the individual resistances.

For the first group: 1/R_eq1 = 1/(1.6 * 10^2) + 1/(1.6 * 10^2) + ... + 1/(1.6 * 10^2) (8 times)

Simplifying the equation: 1/R_eq1 = 8/(1.6 * 10^2)

Now, let's calculate the equivalent resistance for the second group. It consists of 10 lamps, each with a resistance of 2.0 * 10^2 Ohms.

For the second group: 1/R_eq2 = 1/(2.0 * 10^2) + 1/(2.0 * 10^2) + ... + 1/(2.0 * 10^2) (10 times)

Simplifying the equation: 1/R_eq2 = 10/(2.0 * 10^2)

To find the total resistance (R_total) of the circuit, we can use the formula for resistors in parallel:

1/R_total = 1/R_eq1 + 1/R_eq2

Simplifying the equation: 1/R_total = 8/(1.6 * 10^2) + 10/(2.0 * 10^2)

Now, we can calculate the total resistance (R_total) by taking the reciprocal of both sides of the equation:

R_total = 1 / (8/(1.6 * 10^2) + 10/(2.0 * 10^2))

Next, we can calculate the total current (I_total) using Ohm's Law:

I_total = V / R_total

where V is the voltage (220V) and R_total is the total resistance.

Now, let's calculate the values.

Calculation:

For the first group: 1/R_eq1 = 8/(1.6 * 10^2) = 0.05

For the second group: 1/R_eq2 = 10/(2.0 * 10^2) = 0.05

For the total resistance: R_total = 1 / (0.05 + 0.05) = 10 Ohms

For the total current: I_total = 220V / 10 Ohms = 22 Amperes

Therefore, the total resistance in the circuit is 10 Ohms and the total current is 22 Amperes.

Please note that the calculations provided are based on the given information and assumptions about the circuit.