Question

Тепловой двигатель за цикл получает от нагревателя энергию, равную 700 Дж, и отдаёт холодильнику энергию 500 Дж. Чему равен КПД теплового двигателя? (в %). решение с формулай

Answer 1

Ответ:

Формула=(Q1-Q2/Q1)*100%

Ответ(1000-700/1000)*100%=30%

надеюсь правильно!

Удачи:)

Answer 2

Calculation of Efficiency (КПД) of a Heat Engine

To calculate the efficiency (КПД) of a heat engine, we need to use the formula:

КПД = (Energy Output / Energy Input) * 100%

In this case, the energy input is given as 700 J (received from the heater) and the energy output is given as 500 J (given to the refrigerator).

Substituting these values into the formula, we get:

КПД = (500 J / 700 J) * 100%

Simplifying the expression, we have:

КПД = (5/7) * 100%

Calculating further, we find:

КПД = 71.43%

Therefore, the efficiency (КПД) of the heat engine is approximately 71.43%.

Please note that the calculation assumes ideal conditions and does not take into account any losses or inefficiencies in the heat engine system.

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