Question

Двое детей весом 40 кг по очереди прыгают со стационарной машины весом 100 кг со скоростью 1 м / с в одну сторону. Какова скорость тележки? Предположим, что машина и дети образуют замкнутую систему.

Answer 1

Ответ:в школе делали

Объяснение:

Answer 2

Calculation of the Cart's Velocity

To calculate the velocity of the cart, we can use the principle of conservation of momentum. According to this principle, the total momentum before the children jump is equal to the total momentum after they jump.

The momentum of an object is given by the product of its mass and velocity. In this case, we have two children with a combined mass of 40 kg and a stationary cart with a mass of 100 kg. The children jump with a velocity of 1 m/s in one direction.

Let's denote the velocity of the cart as v. Since the system is closed, the total momentum before the jump is zero (since the cart is stationary), and the total momentum after the jump is also zero.

The momentum of the children before the jump is given by the product of their mass and velocity, which is 40 kg * 1 m/s = 40 kg·m/s. The momentum of the cart after the jump is given by the product of its mass and velocity, which is 100 kg * v.

According to the conservation of momentum, we can write the equation:

40 kg·m/s + 0 kg·m/s = 0 kg·m/s + 100 kg * v

Simplifying the equation, we get:

40 kg·m/s = 100 kg * v

To find the velocity of the cart (v), we can rearrange the equation:

v = (40 kg·m/s) / 100 kg

Calculating the value, we find:

v = 0.4 m/s

Therefore, the velocity of the cart is 0.4 m/s.

Please note that this calculation assumes an idealized scenario where there are no external forces acting on the system and no energy losses due to friction or other factors.