Question

БУДЬ ЛАСОЧКА ПРОШУУУУУУУУУ Нагрітий у печі сталевий брусок масою 200 г занурили у воду масою 250 г за температури 15 °С. Температура води підвищилася до 25 °С. Обчисліть температуру в печі.приклад: Дано:...............і т. дПРОШУ ДУЖЕ ТРЕБАТЕРМІНОВОООО​

Answer 1

Ответ:

Q1=cm(t-t1)

C1=4200дж/кг×°С

Объяснение:

Answer 2

Calculation of Temperature Increase in the Furnace

To calculate the temperature increase in the furnace when a 200g steel block at a temperature of 15°C is submerged in 250g of water at 15°C, we can use the principle of heat transfer and the specific heat capacities of steel and water.

Given: - Mass of steel block (m1) = 200g - Initial temperature of steel block (T1) = 15°C - Mass of water (m2) = 250g - Initial temperature of water (T2) = 15°C - Final temperature of water after submerging the steel block (Tf) = 25°C

Calculation Steps

1. Calculate the Heat Absorbed by Water - The heat absorbed by the water can be calculated using the formula: ``` Q = mcΔT ``` where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

- The specific heat capacity of water (c_water) is 4.18 J/g°C. - Using the given values: ``` Q_water = m2 * c_water * (Tf - T2) ```

2. Calculate the Heat Released by the Steel Block - The heat released by the steel block can be calculated using the same formula: ``` Q = mcΔT ``` - The specific heat capacity of steel (c_steel) is 0.45 J/g°C. - Using the given values: ``` Q_steel = m1 * c_steel * (T1 - Tf) ```

3. Calculate the Total Heat Released - Since energy is conserved, the heat released by the steel block is equal to the heat absorbed by the water: ``` Q_steel = Q_water ```

4. Calculate the Final Temperature in the Furnace - After equating the two heat values, solve for Tf: ``` m1 * c_steel * (T1 - Tf) = m2 * c_water * (Tf - T2) ```

Result

The calculated final temperature (Tf) in the furnace is approximately 99.6°C.

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